6을 찾으시오(3개)

쉽다 ㅇㅈ??

a="888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888868888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888688888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888868888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888"

for i in range(len(a)):
if a[i] == '6':
print(f"{i+1}번째에 6이 있습니다!")

251번째에 6이 있습니다!
346번째에 6이 있습니다!
467번째에 6이 있습니다!

코딩쓰는건 에바아니에요??????

몇 행 몇 열인지 찾아보세요(문제 바뀜)

888888888888888888888888888

888888888888887888888888888

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888888888888883888888888788

888788888888888888888888888

888888888888888887883888888

888888888888888888888888888

888788888888888888888888888

8883888"6"8883888888888888888

888888888878888388888888888

888888888888888888888888888

888888888888888888888"6"88888

888888888888888838888888888

888888888888888888888888888

888888388888888888883888888

888888888888888888888888888

8888888"6"8888888888888883888

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코딩 쓰는 것이 어떻게 에바죠!? 혹시나 싫으시다면 본인도 하시면 "됩.니.다.만..?"

귀찮아요